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- © Duncan Williamson
- April 2002
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- The problem that this presentation is designed to help you solve is to
- Maximise π = 4a + 3b
- Subject to: 21a + 16b ≤ 336
- 13a + 25b
≤ 325
- 15a + 18b
≤ 270
- a, b
≥ 0
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- The optimum level of output, therefore, is
- 16 units of a
- 0 units of b
- giving the maximum profit of 64
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- That’s my introduction to the graphical solution to a two variable,
three constraint Linear Programming problem
- You can replay the demonstration as much as you like, of course.
- © Duncan Williamson April 2002
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